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(a) What is the average power output of a heart defibrillator that dissipates 400 J of energy in 10.0 ms? (b) Considering the high-power output, why doesn’t the defibrillator produce serious burns?
(a) $P=4.00 \times 10^{4} \mathrm{W}$(b) The defibrillator does not cause serious burns because a gel is applied to the defibrillator pads before using them. The gel acts as a conductor of the electric current at the metal-skin interface. This is due to the high resistance of the skin, so without this gel, the patient will get bad burns.
Physics 102 Electricity and Magnetism
Chapter 19
Electric Potential and Electric Field
Electric Charge and Electric Field
Gauss's Law
Electric Potential
Simon Fraser University
Hope College
University of Sheffield
McMaster University
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All right. So in this problem, we have a defibrillator and the energy of this defibrillator ah, transferred to the human body is, uh, equal 400 jos. And in time is ah, two minutes seconds. Some party. And we want to find out the power of the city five later. So according to the definition of the power Pequot E over tea. So this gives you four times 10 to the 10 to the fourth waltz, right? So a ce you can see that this very is actually very large And the Why so? So why The defibrillator will not to get the people I'll get to the human body. Ah, in bra burnt. So that's because there is actually a girl between the defibrillator and hadn't been taking the body and this gale access Ah, conductor of the electric current at the Meadow ski interface. So basically, because the human body, because the schemes actually has a very high resistance and with the existence of this ah, the scale, the electron can just flow. Ah, flow Ah, inside the scale and not not not know understand the human body, so that will prevent the human body from getting burned. So that's the reason
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