Problem 15

(a) The electrostatic force (not energy) of attra…


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Problem 14

(a) What is the electrostatic potential energy (in joules) between two protons that are separated by 62 pm? (b) What is the change in potential energy if the distance separating the two is increased to 1.0 nm? (c) Does the potential energy of the two particles increase or decrease when the distance is increased to 1.0 nm?


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Video Transcript

Okay, guess today we're doing being problem. Fourteen in chapter five of chemistry, The central science. So we're gonna be looking at the the interaction between two protons on capturing electrics like Angie. This is a three part question. So in part A, we're going to look at what the The potential energy of these electric like pretences when there's separated by two by sixty two people meters. So we sow with me. The cartridge proton were used The elementary charge one point six zero times, ten to the negative nineteen Cool ums for an electron on a positive charge. Particles at one point six it is It's negative. One point six times scented negative nineteen cool ums. We're getting our kay's April nine nine times ten to nine doing science in your square over Julian squared and our radio and it isn't between them. It's extra pekka meters or sixty two time sending of twelve meters. So we're gonna plug this in and because Kyu Won and Q two are the same, they're both protons. We're going to put it's we're going to just square one point six year times ten to the negative nineteenth. Now we divide by sixty two times I'm it's tend to negative twelve meters twelve So the potential energy of its interaction is three point seven one times. Tend to the negative eighteenth Jules. Now we're going to look at how how the energy changes when we increase the distance to one animator. So one enemy is equivalent to one time sent the negative knife meters. So we're going to do this again, but instead that's it. But instead of RR one we're going to input are two k Q k q p squared R over our too to you. Plug in our numbers and we get there two point three two point three zero times ten to the negative nineteen. If Jules no, you can see that as thanks the that as we increase our distance thie potential energy between our two protons that actually decreased. So when is generally for electrostatic interactions positive as if you have positive you value. That means that you have a repulsive interaction and if you of a negative you value, that means you have an attractive interaction. Action. So, broadly speaking, you can kind of look at it like this. This you can see, see the graph on the right. This is what it looks. These air What? How your energy changes agents as you increase your R value. So this would be that's a positive as a repulsive interaction. As you in Crete issue our value, you're pulling too. Two parts of the charge are things further, further apart, and so the energy of your system, the system is going to slowly drop and then go go to zero because if they're far enough away, then there's going to no interaction whatsoever. There's going to be no potential energy you can measure. Similarly, if you have a negative of a negative charge and a positive charge together and you pull them for their further way, part part, they you're going, I can have that terrible, attractive interaction. So you're and she's going to decrease. Your energy is going to increase. And then us us, your auntie's one increasing and level off zero. So it's not confusing. I'm going to change this. This e too. Are you two? Are you value? Thank you.

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