00:01
So now we'll work on problem 20 from chapter 6.
00:07
In this problem, we are asked, what is the frequency of radiation whose wavelength is 0 .86 nanometers? so we need to remember the relationship between frequency and wavelength.
00:32
So the speed of light is equal to frequency times wavelength.
00:42
So wavelength frequency will be equal to the speed of light over wavelength.
00:52
And we know the speed of light is equal to 2 .998 times 10 to the 8 meter per second.
01:04
And the wavelength is given at the problem, the 0 .86 nanometers.
01:08
But we need to make sure that we account for the units here.
01:14
So we're going to write 0 .86 times 10 to the minus 9 meters.
01:24
So we see that meters will cancel, and it gives us seconds to the minus 1 or hertz.
01:34
So we have 3 .5 when we do the calculation times 10 to the 17th hertz.
01:44
If we wanted to write this without scientific notation, we would have to write 350.
01:50
350 peta hertz.
02:00
It's capital p for 10 to the 15th power.
02:07
So for part b, we're asked, what is the wavelength of radiation that has a frequency of 6 .4 times 10 to the 11 seconds minus 1...