00:01
This problem has two parts to it.
00:03
We have, we're actually given in this equation where beta is the gain, and we have 10 times log of the power output divided by the power input.
00:15
And the first part says if your output is 135 and your input is 1 milawatt, what is the gain? so we're just going to literally plug this in.
00:27
It shouldn't be too difficult.
00:28
So we'll plug in 135 for the power out.
00:31
And then instead of just putting 1 at the bottom, we have to do 1 times 10 to the negative 3.
00:38
And the reason why is because this is milly and a milly watt is equal to 1 times 10 to the negative 3 watts.
00:49
So that's just a conversion there to get that to be what we want it to be.
00:53
When you plug that into the calculator, what you end up getting is, let's try it, 10 times log of 135 ,000 ,000.
01:02
Divided by 1 times 10 to the negative 3 gives us a decibel.
01:08
Remember this is in decibels, 51 .3 decibels.
01:14
So that's the first part of the question.
01:17
The second part says, well, what if we have 93 decibels as our gain? and that's going to equal 10 times log times.
01:26
And they give us a power output of 10 watts.
01:29
And they want to know what is the power input.
01:31
At this point, you're just going to, again, use the same equation.
01:36
You saw me plug in each step.
01:39
You know, the gain is 93 decibels, 10 times log...