00:01
So this question belongs to the fluid mechanics and for the part a we have to determine the largest average velocity of the fluid flow in artery of radius small r equals to 2 multiplied by 10 to the power minus 3 meter and if the flow must remains laminar.
00:16
Okay.
00:17
So for the for the blood we can write that viscosity eta it is equals to 2 .084 multiplied by 10 to the power minus 3 pascal second and the density of the blood, it is equal to 1 .06 mudplied by 10 to the power 3, kilogram per meter cube, and the maximum renol number for the laminar flow, it is 2000.
00:43
So the largest average velocity of the blood, this will be equals to this v, this is equal to renoll number modplied by eta divided by density mudplared by diameter d.
00:55
And diameter d, it can be written as two times of radius, so hence, substituting the value so we get 2000 multiplied by eta which is 2 .084 multiplied by 10 to the power minus 3 divided by density which is 1 .06 multiplied by 10 to the power 3 multiplied by 2 and radius which is this value so 2 multiplied by 10 to the power minus 3 meter so from here largest velocity v comes out to be 0 .983 meter per second so this become the answer for the part a of the problem okay now moving to the part b which says that what is the corresponding flow rate.
01:37
So we have to determine here corresponding flow rate that is q...