00:01
We are told a population has mean mu equals 8 .8 and are given in the following sample data randomly selected from that population.
00:08
From that sample data, we want to calculate the mean x bar and the sample standard deviation s.
00:14
So to do so, let's remember the formulas for each of these terms.
00:18
Sample mean x bar is defined as the sum of the data divided by n, in this case 7 .36.
00:23
And the sample standard deviation is defined as a sum of the deviations about the mean squared, all divided by n minus 1.
00:28
In this case, 4 .03.
00:31
Next, what we want to do is use the sample data to implement a two -tailed test.
00:36
That is, we want to test whether or not the sample data suggests the actual mean of the population differs from the known mean of 8 .8 in either direction, higher or lower.
00:45
We want to use significance level alpha equals 0 .05, and we note at this point that x is approximately normally distributed.
00:51
So, to answer this test question, we have to go through the following procedures in order to finalize the solution to this test.
00:59
Test.
01:00
So first, what are the significance level in hypotheses? off is equal 0 .05.
01:05
No hypothesis h -0, mu equals 8 .8...