Download the App!

Get 24/7 study help with the Numerade app for iOS and Android! Enter your email for an invite.

(a) What is the magnitude of the momentum of a $10,000-k g$ truck whose speed is 12.0 $\mathrm{m} / \mathrm{s} ?$ (b) What speed would a $2,000-\mathrm{kg}$ SUV have to attain in order to have (i) the same momentum? (ii) the same kinetic energy?

Get the answer to your homework problem.

Try Numerade free for 7 days

Like

Report

a. $1.20 \times 10^{5} \mathrm{kg} \cdot \mathrm{m} / \mathrm{s}$b. (i) $60$ m/s (ii)26.8 $\mathrm{m} / \mathrm{s}$

Physics 101 Mechanics

Chapter 8

Momentum, Impulse, and Collisions

Moment, Impulse, and Collisions

Rutgers, The State University of New Jersey

Hope College

McMaster University

Lectures

04:30

In classical mechanics, impulse is the integral of a force, F, over the time interval, t, for which it acts. In the case of a constant force, the resulting change in momentum is equal to the force itself, and the impulse is the change in momentum divided by the time during which the force acts. Impulse applied to an object produces an equivalent force to that of the object's mass multiplied by its velocity. In an inertial reference frame, an object that has no net force on it will continue at a constant velocity forever. In classical mechanics, the change in an object's motion, due to a force applied, is called its acceleration. The SI unit of measure for impulse is the newton second.

03:30

In physics, impulse is the integral of a force, F, over the time interval, t, for which it acts. Given a force, F, applied for a time, t, the resulting change in momentum, p, is equal to the impulse, I. Impulse applied to a mass, m, is also equal to the change in the object's kinetic energy, T, as a result of the force acting on it.

03:09

(a) What is the magnitude …

02:39

01:33

07:03

02:54

1. (a) What is the magnitu…

03:54

$\cdot \mathrm{A} 1200 \ma…

01:01

What is the magnitude of t…

02:04

At what speed does a 1000 …

01:28

(a) What is the momentum o…

00:54

03:38

At what speed does a $1000…

08:44

A pickup truck (2268 kg) a…

07:12

A pickup truck $(2268 \mat…

in this question. We have a truck that is moving safe, the right with velocity off 12 m per second on the mass off the truck is 10,000 kg. Given that we have to calculate the magnitude off the momentum for that, we can use this expression which tells us what is the magnitude off the momentum. According that expression, the magnitude off the momentum is given by the product off the mass which is 10,000 by the velocity which is 12. We can write the mass as 10 to the fourth on the velocity as 1.2 times 10 on these results in the momentum off 1.3 times 10 to the fifth kilograms, times meters per seconds. On this is the answer to the first item off this question. In the second item, an SUV is moving with some unknown velocity V to the right, say on it has a mass off 2000 kg. In the first item off the second item, we have to calculate what should be the velocity off the SUV. In order for this momentum to be equal to the momentum off the truck so we can use the equation for the magnitude of the momentum. P is equals to the mass off the SUV times the velocity off the SUV. We want the momentum off the SUV. Toby equals to the momentum off the truck. These results in the following 1.2 times stand to the fifth should be equal to the mass off the SUV, which is 2000 times its velocity. Then the velocity of the SUV is equals to 1.2 times 10 to the fifth, divided by 2000, which we can write as two times 10 to the third, and then we just have to do the calculation. So we cancel out three turns off 10. So we're left with them to the second in the numerator. Then you simplify here. So we have 0.6 under reform. The velocity is 0.6 times stand to second or 60 m per second on this is the answer for the first item off the second item. Now, for the second item off the second item, we want Signet IQ energy off the SUV to be the same as the kinetic energy off the truck that is moving with 12 m per second off velocity with the mass off 10,000 kg. So remember that expression for the kinetic energy is this one. The kinetic energy is half m times V squared. What do you want? Is that the kinetic energy off the S E V to be the same as the kinetic energy off the truck? So these results in the following the mass off the SUV times the velocity off the S U V, which will calculating this item divided by two and the velocity squared should be equals to the mass off the truck times the velocity off the truck squared, divided by two. These results in the following 2000 kg times the velocity off the SUV. Let me call this V s Divided by two should be equals to the mass off the truck, which is 10,000 kg times its velocity 12 squared, divided by two. Then, as you can see, we can already get rid of these factors off to. And then we solve this equation for the velocity off the SUV. By doing that to get the following the velocity of the S. U V squared is given by 10,000 times 12 squared, divided by 2000, we can simplify 10,000 with 2000. And this is very easy because this division results in five. The reform The velocity off the S U V is equal to the square it off five times 12 squared. This is the square root off five times the square root off 12 squared the square root off 12 squared is 12 off course and then we have the square root off five and then we can approximate the square root off five so that the final result is a velocity off approximately 26.8 m per second on this is the answer to the second item off the second item.

View More Answers From This Book

Find Another Textbook

Numerade Educator

01:52

A 100 000-lb freight car is drawn 2500 ft up along a 1.2% slope at constant …

02:40

A 75.0-kg ice skater movingat 11.4 m/s crashes into a stationary sk…

04:26

Can someone help by writing the equation withoutvariables as well as dra…

02:42

Locate the image of an object placed 1.2m from the vertex of agypsy’s cr…

08:32

4. The equation of a transverse wave in a cord is given by:y(t) = (12.0 …

02:41

A pendulum has a period of 2.50 s on Earth.What is its period on Mars, w…

02:17

A small, 250 g cart is moving at1.60 m/s on a frictionless track when it…

06:24

A 17.0-L tank of carbon dioxide gas (CO2) is ata pressure of 9.90 ✕ 105 …

03:10

A force of 250 N is applied to a hydraulic jack piston that is0.01 m in …

02:10

How long does a harp string need to be for the wavelength ofvibration (f…