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(a) What is the minimum width of a single slit (in multiples of $\lambda$ ) that will produce a first minimum for a wavelength $\lambda$ ? (b) What is its minimum width if it produces 50 minima? (c)1000 minima?
A. $D_{\min }=1.0 \lambda$B. $D=50 \lambda$C. $D=1000 \lambda$
Physics 103
Chapter 27
Wave Optics
University of Michigan - Ann Arbor
Hope College
University of Sheffield
McMaster University
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the minimum worked off. The slit is given by D um M times a Lambda divided by scientists Science for a first minimum that M is equal to one. Then our d becomes Alemdar, derided by science ADA So now D is dependent on the theater. Well, science did, uh, when the scientist is a maximum, then d becomes a minimum. Therefore, scientist isn't is a maximum when it is equal to one. So then d is equal to Linda. This was about a in part B. We are asked to find the minimum d for a musical to 50 for their musical to 50. This becomes simply D is equal to 50 times Linda. So 50 linda inbox see were asked to find If M is equal to 1000 then using the same procedure than the D minimum will be equal to 1000 times the Linda
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