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(a) What is the smallest separation between two slits that will produce a second-order maximum for any visible light?(b) For all visible light?
A. $d_{\min }=760 \mathrm{nm}$B. $d=1520 \mathrm{nm}$
Physics 103
Chapter 27
Wave Optics
University of Washington
Simon Fraser University
University of Sheffield
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smallest separation between the slits is represented by a D that is equal to M times a Linda divided by sign that for M is equal to two. Then it becomes too lender derided by a sign so d becomes a smallest. When that scientist is maximum So scientist is maximum it one so d is equal to to Linda. So So I went signed. That, uh, is one. So we have a diesel called to London for a visible right that ranges from 3 80 nano meter to ah 7 16 and teacher Nanami Jer in part a, uh, we have a deal will be cool too. Two times off, Linda, that is a 3 80 383 80. This gives us the slip separation off 7 69 meter nano meter for ah, for the visible light off prevalent off to 7 60 we have ah, slipped. Separation is two times off. 7 60 That is equal to 1529. We do manager. So the the range off slip suppression is from 7 69 millimeter to 5 29 millimeter
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