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Problem

What is the internal resistance of an automobile …

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Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 Problem 12 Problem 13 Problem 14 Problem 15 Problem 16 Problem 17 Problem 18 Problem 19 Problem 20 Problem 21 Problem 22 Problem 23 Problem 24 Problem 25 Problem 26 Problem 27 Problem 28 Problem 29 Problem 30 Problem 31 Problem 32 Problem 33 Problem 34 Problem 35 Problem 36 Problem 37 Problem 38 Problem 39 Problem 40 Problem 41 Problem 42 Problem 43 Problem 44 Problem 45 Problem 46 Problem 47 Problem 48 Problem 49 Problem 50 Problem 51 Problem 52 Problem 53 Problem 54 Problem 55 Problem 56 Problem 57 Problem 58 Problem 59 Problem 60 Problem 61 Problem 62 Problem 63 Problem 64 Problem 65 Problem 66 Problem 67 Problem 68 Problem 69 Problem 70 Problem 71 Problem 72 Problem 73 Problem 74 Problem 75 Problem 76 Problem 77 Problem 78 Problem 79

Problem 17 Easy Difficulty

(a) What is the terminal voltage of a large $1.54-V$ carbon- zinc dry cell used in a physics lab to supply 2.00 A to a circuit, if the cell's internal resistance is 0.100$\Omega ?$ (b) How much electrical power does the cell produce? (c) What power goes to its load?

Answer

2.9994$V$

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Physics 102 Electricity and Magnetism

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Chapter 21

Circuits, Bioelectricity, and DC Instruments

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Problem 78
Problem 79

Video Transcript

So we're supposed to find the time. It'll voltage in the first part. So terminal voltage is given by M f minus I the current it can supply times the intel new distance am If it's 1.54 as we are given minus the current we are using from the battery is to amperes And the resistance is 0.1. The internal the distances point What? So this will be equal to 1.3 for a vote? Answer On the numerous page is rock. Now for the part B, we are asked to find how much power electrical power does the sell produce power is equal to enough times the current This is equal to three times so sorry 1.54 times, which is the potential signs The current two This would be equal to 3.8 What, in part seeing you are asked how much off it is available to the load as we start in the first part Actual terminal voltages 1.34 fold. So power for the lower will be equal to V Time site which is 1.34 times two. This is equal to 2.68 What? So this instant power available to the load? Thank you

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