Our Discord hit 10K members! 🎉 Meet students and ask top educators your questions.Join Here!

Like

Report

Numerade Educator

Like

Report

Problem 62 Hard Difficulty

(a) What is the wavelength of light for the least energetic photon emitted in the Balmer series of the hydrogen atom spectrum lines? (b) What is the wavelength of the series limit?

Answer

(a) 658 nm
(b) 366 nm

Discussion

You must be signed in to discuss.
Top Physics 103 Educators
Christina K.

Rutgers, The State University of New Jersey

Andy C.

University of Michigan - Ann Arbor

Zachary M.

Hope College

Meghan M.

McMaster University

Video Transcript

Hey, we need to find out what should be the pavement of flight for the least initiative for tone that is emitted in the bomber cities. Off hearts and out of that, the bomber cities corresponds to a transition. Any electron jumps from any specific level in so the final state, too. So whenever you have a transition from any level in tow, the final straight to it is always called a form a line. So this is bomber cities, and we need to find the least energetic for down. In this case, the least energetic photon will be provided, if any, is equal to three, because in that case, the energy difference between the two levels who is least the next should be and equal to form and energy for 24 to 2, with greater than three toe so similarly Tito with the least. So the energy in this case of the Delta of the fourth round, is he clean minus Tito that is equal to minus 13.6, and this comes out this 1.889 TV's. So this is the energy of the least energetic for Don. We can convert this into Waveland And that is given as at sea, your delta, a little guys energy at the concession, which you found out, and this comes out of 650 years. Nanometers. Let's go to a party for the party. We need to find out the city's limit. Now the city's limiters off pain fable end up the city's limit that this friend you have Max highest energy possible. So if this is too Hi, Yes, 90 would be possible if we have a free electron, which is that N is equal to infinity. We have an equal to infinity, and that makes the transition. We get the maximum energy for down. So this is Delta E. Max for the bombing cities. So if I find out the Delta E Max for the Obama cities, that should be energy of this. But the energy of this hysterical equal to zero. So he infinity is equal to zero because we have one over and square and if any is infinity who are noble and square zero. So in this case, the energy simply quit with energy. What? The second level, which is three point forties. You can't let the land off. This which is at sea over. Tell you, Max, you get t 166 centimeters. So this will lose the serious limit prevalent. And this is the longest Rivlin for the bomber cities.

University of Wisconsin - Madison
Top Physics 103 Educators
Christina K.

Rutgers, The State University of New Jersey

Andy C.

University of Michigan - Ann Arbor

Zachary M.

Hope College

Meghan M.

McMaster University