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(a) What magnification is produced by a 0.150 cm focal length microscope objective that is 0.155 cm from the object being viewed? (b) What is the overall magnification if an 8× eyepiece (one that produces a magnification of 8.00) is used?
a. 30b. 240
Physics 103
Chapter 26
Vision and Optical Instruments
Reflection and Refraction of Light
Wave Optics
Rutgers, The State University of New Jersey
University of Michigan - Ann Arbor
Simon Fraser University
University of Winnipeg
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we can find a modification by first finding the distance to the image D I So in about April 1st, find the eye and then unification s o d I can better. Today is from the Formula One over f is a call to win over. The oldest is the object plus one would die from here we will solve for a d I. So this gives us one or F minus one or d o old power minus one. So substituting the values for F in D O, which is for F 0.15 old minus the one to gratify 0.155 old power minus one. This gives us the eye is equal to 4.65 centimeters. We define magnification is called the D. I derived radio, then substituting the values. The tree here is a minus 4.6. So yeah, this is plus five divided by 0.155 So the writing these two numbers gives us 30 here. So, um, unification is 30. Got to be. Then we can find a new identification. Riches them, Let's say their dish. So this is a call to M times and e. So em we have is a 31 deployment here. Is it so 30 minute apply. But it gives us 240.
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