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(a) What magnitude point charge creates a $10,000 \mathrm{N} / \mathrm{C}$ electric field at a distance of 0.250 $\mathrm{m} ?$ (b) How large is the field at 10.0 $\mathrm{m} ?$
a)$q=6.94 \cdot 10^{-8} \mathrm{C}$b)$E=6.25 \frac{\mathrm{N}}{\mathrm{C}}$
Physics 102 Electricity and Magnetism
Chapter 18
Electric Charge and Electric Field
University of Washington
Hope College
University of Winnipeg
McMaster University
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here we are given electric field value as 10,000 new temper Cool. Oh, and we are asked to find the value of charge, which produces the electric field of 10 power four Newtons per cooler electric field formalize given by one by four pipes It or not Q divided by our square are being the distance square, which is also given to US. Surcharge will be equal to 10 powerful times. Distance where distance here is 0.25 squared, divided by nine times 10 power night, which is from factor here, one divided by four pipes it or not. So let's on this. This gives us 6.9 times 10 power Negative eight Coolum Let me write one more digit because in the question we have three significant digits. So 6.94 times 10 pollinated to a TKO. All you can write us 69.4 nano cooler now in the pod be we are asked to find how large is the field at 10 meters. So again, electric field which is equal to one by four pipes are not cute, has a value that we found in the first part which is 69.49 Opal. Um, so let's not try that value yet. Q. Divided by our square. Now we're supposed to find entry field value. We know one by four. Perhaps there are noticed nine times 10 Power nine Valley of Pew is 69.4 times 10 Power negative nine divided by distance is 10 meters, so it will be 10 squared. Let's do this much application off nine and 69.4, which is 6 24.6 times 10 power. Negative too. All 6.25 Newtons were cooler. See that the value has significantly reduced or decreased from the initial value, which was 10,000 new Temple Coolum because electric field decreases as distant square. So thank you for listening.
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