00:01
In this question, we are given that there is a wheel of radius 14 inches and it's rotating at 0 .5 radian per second.
00:06
This is radiant per second.
00:08
What's the linear speed? that is one.
00:10
So the linear speed is omega times the radius.
00:15
That's straightforward formula.
00:16
So omega is already given as 0 .5 radian per second and the radius is given as 14.
00:21
So that's got to be 7.
00:23
7 meter per second.
00:25
So that is the linear speed.
00:27
Then in part b they're talking about the angular rpm so that's where we need to do some calculations because we are given that the speed is 0 .5 radium per second.
00:39
Rpm is revolution per minute.
00:41
Now in 2 pi radiance in 2 pi radiance there is one revolution this is equal to the 1 revolution because one revolution has 2 pi degrees covered 2 by radiance covered.
00:54
So in 0 .5 radiance, in 0 .5 .5 radiance, the number of revolutions has got to be 1 over 2 pi times 0 .5 .5.
01:03
So that will be in revolutions per second because the angular speed is in 0 .5 radiance per second.
01:10
But so this is nothing but 0 .5 over 2 pi.
01:15
But we are interested in revolution per minute.
01:18
So if we have to convert the second to minute, then we have to multiply that about 1 over 16...