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Problem 18

(a) When a compound containing $\mathrm{C}, \math…

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Problem 17

(a) When the metallic element sodium combines with the nonmetallic element bromine, $\mathrm{Br}_{2}(l),$ what is the chemical formula of the product? (b) Is the product a solid, liquid, or gas at room temperature? (c) In the balanced chemical equation for this reaction, what is the coefficient in front of the product if the coefficient in front of $\mathrm{Br}_{2}(l)$ is 1$?$

Answer

a) $\mathrm{NaBr}$
b) solid
c) 2


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Video Transcript

for this coercion, sodium and a is a metal that belongs to a group number one. Thus it forms. I am with positive one charge giving us any positive vibe. Roomie is a non metal that belongs to a Group 17. US commonly forms iron, with negative one charge. Be on negative in an ionic compound. These two iron, the total positive charge, must be equal to zero. The any compound must be overall neutral, so each Saudi mind requires one bromide iron to neutralize the positive one charge. Therefore, the chemical formula for the product will be n e br for auction. Be almost all the I nicked compounds are solid for option C. The chemical equation for the given reaction is and e plus br too. Giving us an e bill balanced the number off Ramin atom by changing the coefficient off in a beer on the right hand side, leading us to and a plus B R two giving us two and a BR. Now the number of sodium atom is changed. Balanced them by changing the coefficient off. Any to do on the left hand side, so it will be too. And a plus. B. I to giving us to any beer. Therefore, to balance the chemical equation without changing the coefficient off. We are too. The genes coefficient off, the product will be two.

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