00:01
So we have a three -part question here.
00:03
First of all, where does this line intersect this plane? well, we can just plug in the values for x, y, and z in the line.
00:14
If we have this, we can say r of t equals as an x, y, z coordinate that is 2 plus 3t on the i component, 5 plus t in the j or y component, and then this is just 2t in the z, which is the k component, and then plug that into our plane equation here.
00:43
We need 2 plus 3t plus 5 plus t plus 2t to equal 1.
00:52
There's our x, our y, and our z.
00:55
Combining like terms here, we have 2 plus 5 is 7, plus 3 plus 1 plus 2 is 6.
01:04
6t equals 1.
01:06
So t, if we subtract 7 from either side, 6t equals negative 6, so t equals negative 1.
01:14
And then plugging t equals negative 1 into all this, 2 plus 3 times negative 1 is negative 1, 5 minus 1 is 4, 2 times negative 1 is negative 2.
01:25
So that is where we intersect the plane.
01:30
Next up, find a vector perpendicular to the line that lies in the plane.
01:35
Well, let's see...