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Problem 52

(a) Which substance in Table 5.2 requires the smallest amount of energy to increase the temperature of 50.0 g of that substance by 10 K? (b) Calculate the energy needed for this temperature change.

Answer

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## Discussion

## Video Transcript

All right, guys, Today we're going to be doing Chapter five, Question fifty two for for chemistry that Central science. We have our table five point to here with a bunch of different samples. Now we need to find the sample that's going to required the least amount of energy eight to raise fifty grands that sample by ten degrees. Kelvin. So let's look at our different samples. So we have nitrogen, aluminum, iron, iron, mercury, water, methane cover your backside and calcium carbonate. So we talked to like the amount of energy energy needed for this kind of transition is informing like cubicles empty Delta T Garcias are specific heat which are which are these values the amount of energy needed to raise one gram of the substance by one degree. So we ever delta t value and our Matthew just thie fifty grams. So So, since our mass is constant and our delta teams constant, the only variable is C. So I think you know what sample you can think of Energy too. Through the increase is ten degrees, ten. Ten. Kelvin, we just need to look at the sample that has the the lowest he can pass either is and it looks us, and it looks like that is Mercury with point one for Jules program Kelvin Children. Now they want us to kept now party. They want to calculate at the energy from the transition, so Q is equal to fifty point zero grams time point one four Jules per gram Kelvin planned by ten Calvin. The cue is equal to then. So if they will take seventy Jules to increase fifty that's fifty grams of our mercury by ten by ten Calvin.

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