00:01
We are asked to solve two problems for this section.
00:04
First, we're asked to predict whether a cobalt hydroxide, a cobalt two hydroxide precipitate will form from a cobalt nitrate, cobalt two nitrate solution.
00:19
We're given the following information.
00:25
The ph of the solution is 8 .5, and we have a 0 .020 .0 .2.
00:41
Zero molar solution of cobalt nitrate, cobalt two nitrate.
00:54
Let's go ahead and write down our equation, whoops, that's solid.
01:26
Now let's find out what our cobalt ion concentration is.
01:35
Our cobalt nitrate, cobalt two nitrate, will dissociate 100%.
01:54
So if we have a 0 .020 molar, c -a -n -o -3, or that's c -o -c -o -n -3 -2.
02:08
That means we have 0 .0 -0 -2 -molar cobalt concentration.
02:15
There's my cobalt ion concentration.
02:19
I'll switch colors for the o -h concentration.
02:26
In order to do this, we're going to convert ph to p -o -h, and then we're going to use 10 to the negative p -o -h to get the concentration.
02:44
To convert ph to p -o -h, we are simply going to take 14 minus 8 .5 equals 5 .5.
02:56
That's my p -o -h.
02:59
10 to the minus 5 .5.
03:03
10 to the minus 5 .5.
03:05
I'm looking for my work here.
03:10
Gives me a, what does that say? 3 .162 times 10 to the minus 6th.
03:29
To find our q, let's multiply our cobalt concentration.
03:39
I'll switch colors again here.
03:43
Our cobalt concentration is 0 .020.
03:47
I'm going to leave my units off.
03:52
And then the oh concentration 3 .162 times 10 to the minus 6 squared.
04:06
Q equals 2 .0 times 10 to the minus 13th.
04:20
The ksp for cobalt 2 hydroxide is 1 .3 times 10 to the minus 15th.
04:43
Q is greater than the ksp...