Question
A wire can sustain the weight of $20 \mathrm{~kg}$ before breaking. If the wire is cut into two equal parts, each part can sustain a weight of(A) $10 \mathrm{~kg}$(B) $20 \mathrm{~kg}$(C) $40 \mathrm{~kg}$(D) $80 \mathrm{~kg}$
Step 1
Step 1: We are given that a wire can sustain a weight of 20 kg before breaking. Show more…
Show all steps
Your feedback will help us improve your experience
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A wire can sustain the weight of 20 kg before breaking. If the wire is cut into two equal parts, each part can sustain a weight of
A wire can be broken by applying a load of $20 \mathrm{~kg}$ wt. The force required to break the wire of twice the diameter is (a) $20 \mathrm{~kg} \mathrm{wt}$ (b) $5 \mathrm{~kg} \mathrm{wt}$ (c) $80 \mathrm{~kg} \mathrm{wt}$ (d) $160 \mathrm{~kg}$ wt
When more than 20 kg mass is tied to the end of wire it breaks what is maximum mass that can be tied to the end of a wire of same material with half the radius ? (A) 20 kg (B) 5 kg (C) 80 kg (D) 160 kg
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD