Question
A wire carries a steady current of $2.40 \mathrm{~A}$. A straight section of the wire is $0.750 \mathrm{~m}$ long and lies along the $x$ axis within a uniform magnetic field of magnitude $B=1.60 \mathrm{~T}$ in the positive $z$ direction. If the current is in the $+x$ direction, what is the magnetic force on the section of wire?
Step 1
The formula is given by: \[ F_B = I \vec{L} \times \vec{B} \] where \( F_B \) is the magnetic force, \( I \) is the current, \( \vec{L} \) is the length vector of the wire, and \( \vec{B} \) is the magnetic field vector. Show more…
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A wire carries a steady current of 2.40 A. A straight section of the wire is 0.750 $\mathrm{m}$ long and lies along the $x$ axis within a uniform magnetic field, $\overrightarrow{\mathbf{B}}=1.60 \hat{\mathbf{k}} \mathrm{T}$ . If the current is in the $+x$ direction, what is the magnetic force on the section of wire?
A wire carries a steady current of $2.40 \mathrm{A} .$ A straight section of the wire is 0.750 m long and lies along the $x$ axis within a uniform magnetic field, $\mathbf{B}=1.60 \mathbf{k}$ T. If the current is in the $+x$ direction, what is the magnetic force on the section of wire?
A wire carries a steady current of 2.40 A. A straight section of the wire is $0.750 \mathrm{~m}$ long and lies along the $x$ axis within a uniform magnetic field, $\overrightarrow{\mathbf{B}}=1.60 \mathbf{k}$ T. If the current is in the positive $x$ direction, what is the magnetic force on the section of wire?
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