Question
A wire of length $l$ is bent to form a circular coil of some turns. A current $I$ is then established in the coil and it is placed in a uniform magnetic field $B$. The maximum torque that acts on the coil is :(a) $I B l^{2}$(b) $4 \pi I B l^{2}$(c) $\frac{n^{2} B}{4 \pi}$(d) zero
Step 1
The length of the wire $l$ is equal to the circumference of the coil, which is $2\pi r$ times the number of turns $n$. So we have: \[l = 2\pi r n\] From this, we can solve for $r$: \[r = \frac{l}{2\pi n}\] This is our equation 1. Show more…
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A wire of length, $l$ is bent in the form of circular coil of some turns. A current, $i$ flows through the coil. The coil is placed in a uniform magnetic field, $B$. The maximum torque on the coil can be (a) $\frac{i B l^{2}}{2 \pi}$ (b) $\frac{i B I^{2}}{4 \pi}$ (c) $\frac{i B l^{2}}{\pi}$ (d) $\frac{2 i B l^{2}}{\pi}$
Magnetic Effect of Current
Round 1
Current $i$ is carried in a wire of length $L$. If the wire is turned into a circular coil, the maximum magnitude of torque in a given magnetic field $B$ will be (A) $\frac{L^{2} i B}{2}$ (B) $\frac{L^{2} i B}{\pi}$ (C) $\frac{L^{2} i B}{4 \pi}$ (D) $\frac{L i^{2} B}{4 \pi}$
Current $i$ is carried in a wire of length $L .$ If the wire is turned into a circular coil, the maximum magnitude of torque in a given magnetic field $B$ will be (A) $\frac{L^{2} i B}{2}$ (B) $\frac{L^{2} i B}{\pi}$ (C) $\frac{L^{2} i B}{4 \pi}$ (D) $\frac{L i^{2} B}{4 \pi}$
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