Question
A wire suspended vertically from one of its ends is stretched by attaching a weight of $200 \mathrm{~N}$ to the lower and. The weight stretches the wire by $1 \mathrm{~mm}$. Then what is the elastic energy stored in the wire?(A) $0.1 \mathrm{~J}$(B) $0.2 \mathrm{~J}$(C) $10 \mathrm{~J}$(D) $20 \mathrm{~J}$
Step 1
Step 1: The formula for the elastic potential energy stored in a stretched wire is given by $\frac{1}{2} F \Delta x$, where $F$ is the force applied and $\Delta x$ is the displacement or stretch in the wire. Show more…
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A wire suspended vertically from one of its ends is stretched by attaching a weight of $200 \mathrm{~N}$ to the lower end. The weight stretches the wire by $1 \mathrm{~mm}$. The elastic energy stored in the wire is (A) $0.2 \mathrm{~J}$ (B) $10 \mathrm{~J}$ (C) $20 \mathrm{~J}$ (D) $0.1 \mathrm{~J}$
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