a-wooden-block-experiences-a-frictional-force-f-as-it-slides-across-a-table-if-a-block-of-the-same-m

Question

A wooden block experiences a frictional force, f, as it slides across a table. If a block of the same material with half the height and twice the length were to slide across the table, what would be the frictional force it experienced?
(A) (1/2)f
(B) f
(C) 2f
(D) 4f

Vishal Gupta · Accepted Answer

Hi in a given problem. First of all, there is rough surface over which there is a block suppose having a height edge and land L. The block is made up of a wood in the second case the block another block made up of the same wood but having a height huh? That of the first one and land twice that of that first one. So if length is L. Here it is that you the land will be too well and the height will be edge by two. And this is er wooden block. So the wooden block will be having same density in both of the cases as a blog is having seen volume. In both cases the blogs are having same densities and same volume. So these blocks will be having seen moss or we can say same weight as the wheat always x vertically downwards. So the reaction normal reaction exerted by the surface or the block that will be in and which will be equal to MG. Using Newton&#x27;s third law of motion as there is no motion in the block. Long vertical to this end will be equal to MG. No, as force of friction is given as F is equal to new times. Their new is the coefficient of friction. This is mealtimes and and N is seen in both of those situations, so the force of friction will remain the same in both of the cases before. So friction will have insane in second case. Also, that will be equal to smaller. Hence we can see corruption. B is correct. Thank you.

Ze-Han Lee · Answer

So in this problem Ah, block is moving on the table. So the velocity V and we know that there exists the friction. So the friction is Africa. And ah, if you want to find out the force exerted by the table on the block So besides, off this Ah f though the friction, there is also the normal force which is pointing out Ray. So these two, that&#x27;s it is in so at and end this the forces are the only force is excited about table. Yeah, and the combination of them is pointing to some directions actually, So we see that Ah, uh, combine for

Grant Ayers · Answer

Okay, let&#x27;s say we have a 20 Newton object sitting on a flat surface. So 20 Newtons it means that they&#x27;re 20 Newtons down because the acceleration due to gravity will always point down. Run. We play in 18 Newton force to it going to the right and this surface as friction. Just three friction of zero point for. So we know because of Newton&#x27;s second law of Motion that f equals inmate workforce because the mass times acceleration and we&#x27;re looking for the acceleration. So we can say that the 20 Newton Force because we know that there&#x27;s the 20 an object because we know there&#x27;s a, um 10. There&#x27;s an acceleration of 10 meters per second squared on him. You can say that, um 20 Newtons equals the mass, which we don&#x27;t know for this object. Nick celebration. We can round 2 10 for this object. So you know that something times the mass equals 20. So mass equals two. Um, for this objects, it&#x27;s two kilograms. Yes, we have a and now we can solve for the acceleration. We have a two kilogram object. Well, some acceleration that we don&#x27;t know. He calls, so there&#x27;s gonna be two forces here is going to be the force of the 18 Newton&#x27;s moving at is going to be force of the static friction, which will always oppose force in some degree. So not there&#x27;s 18 Newton&#x27;s and we know because the object has acceleration. That actually doesn&#x27;t that moving so 18 Newton&#x27;s minus and to find the force of friction. It&#x27;s just, uh, the friction constant, which is here. Quinn, for in this case, times Newton&#x27;s that the object ways. So zero point for Com&#x27;s, which ends up working out too eight in this case, went for times 20. So you have to times the acceleration equals 18 minus eight, which is 10. So the acceleration times two equals 10 so acceleration cools.

Ze-Han Lee · Answer

All right, So, uh, in this problem, we know that Ah, Block. Which way&#x27;s, uh, 20 new days on the horrors on the plan and the weeks that force extending force F in Africa. Well, 18. Notice the friction, The friction constant. Between the table and the block is mieux que equal 180.4. So we can determine the friction on this book. Which equal? Ah, and G handsome you, Kate. Right. So this gives us eight Newtons sewn f words on this block. It&#x27;s f minus the friction, which is 10. You tease so generation on this. Ah, on this book, equal am pants, eh? A continuities devour the mass because it ah, because it weighs 20. News is so, uh, the masses. Two kilograms. All right, so this gives us five meters per second squared. All right?

Ze-Han Lee · Answer

All right, so in this problem, we have to situations. The 1st 1 is that we have two blocks stacked together and the second wise Ah, we put them side by side. So Ah, the friction force on both cases they&#x27;re actually the same. Their bills equal and handsome. You Sorry to M g times me. Okay, so to m Jimmy&#x27;s the gravity of the total mass and the muse of friction coefficient between the surface of the ground. So, uh, no matter how in which way you put them Ah, the friction. The friction is always the same. So you need thio. Make sure that forces larger than this one thio push the to push them to push them.

Nicholas Majtenyi · Answer

all right. Question 76 asks that a wood block of mass M little M rests on a larger would block of mass Big M that rests on a wooden table. I showed this image here. We can include a little table underneath it to spare completeness, Something like that. Ah, the coefficient of static and connects. Friction between all service is on us and you can&#x27;t, respectively. What is the minimum horizontal force F. So say, after this positive right direction, I applied to the lower block that will cause it to slide out from under the upper block. So both of these scenarios they were dealing with, we&#x27;re starting from rest. So really, why does provide us the coefficient of kinetic friction? Really, all do we have to deal with is a coefficient of static friction. We want to know how much force being applying. So the block moves. That really is a static friction scenario. For me, it is a bit of a throw off here to convince you to use in UK, but we really don&#x27;t need that for this type of problem. So we should look at all the forces that these blocks are experiencing So if you look at this force of static friction for block, I&#x27;ll say it a little in I feel like if you look at 1/4 body diagram of little M, you know that normal force pointing up and then force of gravity is pulling down as it normally is. So the coefficient started the force of friction of little block images from us. Most find by little M times G. Look, if you look at the forces stand efficient for block big M, I don&#x27;t see it will also have the coefficient of static friction ever. Now the mass if we because, for instance, this system has if you push on the lower block, it experiences also the mass of the upper block. The total mass of this thing of system would be the sum of both of these blocks because the No. One force experiences has both components, the lower block and upper block acting on it. So this is begin. It feels the gravity both due to little mg and big energy. If this is block, begin normal of the bottom. Francis nb, Really, if you think the total force required would have to overcome both of these static friction scenario soon it&#x27;s just some of forces due to static friction. What we know, we found each of them are for the top and bottom blocks. So for the upper block, it&#x27;s us little n g. With these lower block and us some of both masses little n plus M times G. And we can simplify this expression, collecting your life terms for em to simply be yes times G. We have two little EMS plus begin so that you know. So this is the net force the minimum force required in order to move a block to the block underneath block one. I want to move it and overcome the static friction.

Problem

Two objects, a sphere and a block of the same mas…

Problem 21 Easy Difficulty

A wooden block experiences a frictional force, f, as it slides across a table. If a block of the same material with half the height and twice the length were to slide across the table, what would be the frictional force it experienced?
(A) (1/2)f
(B) f
(C) 2f
(D) 4f

Answer

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