00:01
Okay, so here we're going to have that mew is equal to $37 ,000, sigma is equal to $4 ,000, and p is equal to $0 .8.
00:08
So in part a, we are considering a random sample of 60 students from this college, and we are interested in computing the probability that less than 70 % of the students from this school have accepted job offers.
00:21
So we're calculating the probability that p hat is going to be less than or equal to 0 .6.
00:31
So we get that mu is equal to p, which is equal to 0 .8.
00:36
Sigma is then equal to the square root of p times 1 minus p all over n.
00:42
That gives us 0 .0516.
00:47
And then the probability here, probability of p hat being less than or equal to 0 .7 is going to be equal to the probability that z is less than or equal to 0 .7, minus 0 .8, all divided by 0 .0 .0516.
01:08
That is going to be equal to the probability that z is less than equal to negative 1 .94, which gives us 0 .062.
01:20
So there we have the probability that less than 70 % of the students from this sample have accepted, the drop offers is going to be 0 .062.
01:30
And then in part b, we consider a random sample of six students from this college.
01:36
So calculating the probability that p hat is less than equal to 0 .7, again, sigma here is going to be equal to the square root of p times 1 minus p over n.
01:45
That's the square root of 0 .8 times 0 .2, all over 6, which gives us 0 .1633.
01:53
And then the probability is going to be equal to the probability that z is less than or equal to 0 .7 minus 0 .8, all divided by 0 .1633, and that is going to be equal to 0 .2709.
02:16
So that's the probability that 70 % of the students from this sample have accepted the job.
02:23
Offers is going to be 0 .2709...