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A worker in the automobile industry works an average of 43.7 hours per week. If the distribution is approximately normal with a standard deviation of 1.6 hours, what is the probability that a randomly selected automobile worker works less than 40 hours per week?

0.0104

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Gretchen G.

October 3, 2020

how did you determine 0.0104? Where did that come from?

Gretchen G.

October 3, 2020

Nevermind

So in this question, drives to find the probably the randomly selected automobile workers were ex lesson four yards per week. So we can read that as the probability X less than where X is the number of hours. Automobile workers in this question were also given a hint, which is that the distribution is approximately normal, which means that we can use this standard distribution formula. Z is equal to thanks over six. And the question Rosa, given that the average number of hours MIA is equal to 40 three, said hours on that the standard deviation Sigma is equal to 1.6 to censor China solve for probably even number of eyes listened. 40. We can put 40 into our equation. So for corresponding Z value So just 40 minus 40 3.7 over six disease, which is the same thing that's right, native to seven over 106 h is equal to think it is 2.31 to 5, so we can run that to two decimal places to get negative 23 and then we're gonna be doing is looking for the corresponding probably for this value in this too. Do that beginning get Teoh you one's for which is their final chance