00:01
This question asks whether chlorination or bromination will give us a greater yield of each of these compounds that have drawn out.
00:09
So a is one, halo, two, three, dimethylbutane right here.
00:14
So this halogen is on, this primary methyl over here.
00:20
These are all the same.
00:22
And there's a total of nine of those types of, sorry, 12 of those types of hydrogen.
00:26
So we'll take 12 and multiply it by the primary.
00:30
Number which is one for both chlorine and bromine.
00:34
And there's two of the other type of hydrogen here, which is tertiary.
00:38
So for chlorine, we'll have 12 times 1 is 12.
00:43
And then for the tertiary hydrogens, we'll have two times five from that chart up above.
00:48
So that's 10.
00:50
And then for bromine, we'll do the exact same thing...