00:01
Okay, so for this question, they want us to write the balanced equation for the formation of one mole of cr2 -o -3 from cr and o2, chromium and oxygen, right? so in their standard state.
00:16
So chromium in their standard state is a solid plus oxygen, o2, is a gas.
00:25
Right, the reason why is o2 is because oxygen is a diatomic molecule, meaning that in their standard state, oxygen is always.
00:31
Present in a pair and this forms cr203 so now we're going to balance out the equation so we see that there is two chromium on the right and there's only one chromium on the left so we put a two in front chromium is now balanced and we see that there is three oxygens on the right while there is only two on the left so if we put a three over two here like that's 1 .5 right 1 .5 times 2 is equal to 3 now oxygen is also balanced now let's look at up appendix l to find the value of delta h for this reaction.
01:13
So if we look that up, we should get delta h is equal to negative 1134 .7 kilojoules per mo.
01:27
And now in the question, they say that we have 2 .4 grams of chromium.
01:32
So what is the center entropy of change of 2 .4 grams of chromium? so let's find out how many moles of chromium is that.
01:41
So 2 .4 grams of chromium, we know that one mole of chromium is equal to, one mole of chromium is equal to 52 grams, right? so 2 .4 divided by 52, we should get 0 .046 moles...