A base is a proton acceptor. So, $\mathrm{HSO}_{4}^{-}(a q)$ will accept a proton (H+) from water to form $\mathrm{H}_{2} \mathrm{SO}_{4}(a q)$ and $\mathrm{OH}^{-}(a q)$. The equation is:
\[\mathrm{HSO}_{4}^{-}(a q) + \mathrm{H}_{2} \mathrm{O}(l) \rightarrow
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