00:01
In problem 3, write balance equation and identify the charge of cation and anion for each of the product.
00:07
So first equation is calcium when it is react with the oxygen, then it will form calcium oxide.
00:16
So this is not a balance equation.
00:19
So in order to balance this equation, what we can do, we can multiply calcium atom in the left hand side by 2.
00:27
So now and in the right hand side calcium oxide by 2 so now it is balance equation so this is the balanced chemical equation and the product is calcium oxide and we identify the charge of cadine and anion for product also so basically it is a calcium oxide so charge on calcium is plus 2 and oxygen is minus 2 another equation is when chromium this reacts with the oxygen then it will form chromium oxide cr2 .3.
01:16
So this is not a balance equation.
01:18
So in order to balance this equation, what we can do? we can multiply in the left hand side of chromium by 4 and this is 3 .2 and this is 2 cr2.
01:33
Now it is the balance equation and the charge on the product side is that means cr2 -03 the product form is cr2 -03 and this oxygen atom is in the minus 2 and this chromium atom is in plus 3 charge.
02:04
So chromium is the metal that is the charge on cation and anion...