We can do this by multiplying the magnitude of each vector by the cosine and sine of its direction angle. For $\overrightarrow{\boldsymbol{A}}$, this gives us $(3.60 \, \text{m} \cos 70^\circ) \hat{\imath} + (3.60 \, \text{m} \sin 70^\circ) \hat{\jmath} = (1.23 \,
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