- The modulus of $\mathrm{i}$ is $|\mathrm{i}| = \sqrt{0^2 + 1^2} = 1$.
- The argument of $\mathrm{i}$, denoted as $\arg(\mathrm{i})$, is $\frac{\pi}{2}$ because $\mathrm{i}$ lies on the positive imaginary axis.
- Therefore, $\mathrm{i}$ in phase-modulus form is
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