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Problem 38 Hard Difficulty

(a) Write out the electronic configuration of the ground state for nitrogen $(Z=7) .$ (b) Write out the values for the possible set of quantum numbers $n, \ell, m_{\ell},$ and $m_{s}$ for the electrons in nitrogen.

Answer

a) 1$s^{2} 2 s^{2} 2 p^{3}$

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Top Physics 103 Educators
Andy C.

University of Michigan - Ann Arbor

Marshall S.

University of Washington

Farnaz M.

Other Schools

Jared E.

University of Winnipeg

Video Transcript

in question eight, We need to find what is the electronic configuration for the nitrogen has an atomic number off seven, which means that he has seven elections and we had to find the electronic configuration in the ground state. So let's start by feeling the one s of show They're two elections, uh, that can fit in the sexual. So since we have seven in the nitrogen, we still have five to go. Then the next step shell is to ask, which also fits too active. So in total, we have four and we still have three to go. The necks of shell is the to P in earth, and six electrons can fit in this of shell. But we'll only have three left. So I feel it with three elections. And this is the electronic configuration off the nitrogen question be we have to find all possible combinations of the quantum numbers and which is the greatest of all Clinton Number L, which is the orbit of from one to number ml in a mess, which are the magnetic and the spin quantum numbers for the electrons in the hydrogen. Adam eso here for we can have an equal one. Okay. In which case l can only be zero and ml since Al zero ml can only be zero and m s can be either plus or minus 1/2. Okay, so there are two states here. I'm just convincing the notation, writing two states in Onley one line because otherwise we're gonna have many lines for n equals one. I'm sorry for an eagles to you have l equals zero or one so we can have Alico zero m l equals zero and m s equals plus or minus 1/2. And for l equals one haven't and two equals two l equals one. Then ml can be either minus 10 or plus one. So if m l is, so have this state for m l equals minus one m s equals plus or minus 1/2. And to Alec was one l equals zero. A mess can be either blows for minus 1/2 and to l it was one and l equals one, and a mass can be either my plus or minus one happen. So these are the all the possible combinations for for the quantum numbers and l m l and M s that represent the state of that. The possible states of the elections in the nitrogen atoms

Universidade de Sao Paulo
Top Physics 103 Educators
Andy C.

University of Michigan - Ann Arbor

Marshall S.

University of Washington

Farnaz M.

Other Schools

Jared E.

University of Winnipeg