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A young woman with normal distant vision has a 10.0% ability to accommodate (that is, increase) the power of her eyes. What is the closest object she can see clearly?

20 $\mathrm{cm}$

Physics 103

Chapter 26

Vision and Optical Instruments

Reflection and Refraction of Light

Wave Optics

Cornell University

University of Michigan - Ann Arbor

University of Washington

Hope College

Lectures

02:51

In physics, wave optics is…

02:30

In optics, ray optics is a…

01:11

The normal power for dista…

01:41

A woman can see clearly wi…

04:02

02:55

A nearsighted woman can’t …

00:38

A nearsighted person canno…

01:35

01:52

A nearsighted patient'…

03:19

Correcting vision A woman …

01:39

$\cdot$ A person can see c…

04:45

A person can see clearly u…

05:26

A certain child’s near poi…

00:43

The power for normal dista…

01:45

A woman can read the large…

00:49

For normal distant vision,…

01:48

A farsighted woman breaks …

02:11

(III) A nearsighted person…

Ellen wears eyeglasses wit…

01:54

(II) A nearsighted person …

A severely myopic patient …

01:21

People who do very detail…

Hey, guys, in this problem, we are told that the, uh, Lindy sees has a normal, distant vision. Right now, however, her eyes can increase her power by 10% 1 needed. And basically the problem is asking us. How far can she see when her basically her vision increases by 10%? The lens to read in the distance is still to put 2.0 centimeters. So first steps first we normal distant. Begin right here. It's normal distance vision right here is always going to be any 50 eye openers. 50 die openers, 15 tie openers and And when the woman is looking, it says that she experiences a 10% increase. Basically, 10% increase means you're multiplying by once when it was 1.10 And that means when the woman can actually see with the power rating of 55 day openers now to conquer how far she can see with her eyes. This is a simple copulation. We know that the power is equivalent to one over d i ah d I it's right that better one over d I minus one plus one over d o. And that means our d O or how far she can see the distance that she can see is equal to the power right here. The 55 eye openers minus one over D i E r d. I is equivalent to our two centimeters the distance from the lens to the retina. So if we plug this in, we get 55 0 this is to the minus one power, by the way. And then that means we get 55 minus one over 0.0 to to the minus one power. And if we go ahead, plug this into our calculator. The answer that we get is we get 0.200 meters or 20 centimeter. That's how far this purse against

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