00:01
Let's find the absolute max in mince for this function.
00:04
F of x equals sine 3x on the interval from negative pi over 4 to pi over 3.
00:11
So to find absolute max in mins, we have to find the critical values where the derivative is equal to 0.
00:17
And then evaluate the critical values and the endpoints in the original function and then see which ones are the largest and smallest outputs.
00:25
So let's find the derivative first.
00:26
F of x so we have a nice chain rule here so uh derivative of sign is going to be cosine keep the inside and then the derivative of the inside of three of x is three so we're going to multiply this by three and so then we get this equals three cosine of three x now i want to know when is this equal to zero well that's only going to happen when the cosine part of it is equal to 0.
01:02
Now when is cosine equal to 0? well, if you just think of a regular cosine theta being 0, well that's when theta is pi over 2, negative pi over 2, 3 pi over 2, and so on.
01:30
And so what we want to know actually is when is 3x equal to these values.
01:40
Now, they can't, obviously, there's infinitely many of these, but because we have this boundary condition, we're only going to have so many.
01:48
And so we're actually having to check and find out.
01:50
So we'll start with the easiest one, pi over two.
01:53
So when is 3x equal to pi over two? well, that's going to be when x equals pi over six.
02:03
So there's the first one.
02:07
And what about when 3x equals 3 pi over 2? oh, well, okay, well then that's when x is going to be equal to pi over 2.
02:22
Oh, but now we have a problem.
02:24
Well, that's not a problem.
02:26
But notice how pi over 2 is bigger than pi over 3.
02:28
So it's actually out of the domain.
02:31
It's out of the boundary.
02:31
So this one we don't have to worry about.
02:33
It's out of bounds, so to speak.
02:42
Okay, what about when 3x equals? negative pi over two.
02:47
Well, okay, well, that's easy.
02:49
It's the same thing we did before, just negative.
02:50
So that means that x is equal to negative pi over six.
02:56
And that's still within our bounds, right? yep.
03:00
And what happens when 3x equals negative, negative 3 pi over 2? once again, that's when x is going to be equal to negative pi over 2.
03:17
But if we look at our boundaries, that is less than pi over 4.
03:23
So once again, this one is out.
03:29
It's out of bound.
03:35
Okay, so now we actually only have two critical values to worry about pi over 6 and negative pi over 6...