00:01
Hello, welcome to this lesson.
00:01
In this lesson we have the rich at which online advertisement revenue grows.
00:11
So we are looking for the amount that is involved.
00:17
Then we will take the integral of the rich.
00:40
Now for us to make the work very simple, we would do a substitution.
00:47
So we will substitute you that is equal to 0 .163 plus 0 .163 times t plus 1 and now the u becomes 0 .163 d t so d t is the u on 0 .163 all right let's find the rear reading which is the integral of the rate.
01:31
So this is now in terms of you.
01:38
So 331 , so in place of the whole thing will put you over there, the place of the t will put the u on 0 .131630 just as we have here.
02:00
Okay and the revenue in terms of you becomes so this is what we have in terms of you this becomes one nine one three e to the power u plus c okay now we'll put back whatever value we had for t earlier to 0 .163 t plus 1 plus c we use the initial value when it was 0 we had the year 2009 and the expenditure the revenue stood at 22 .7 billion 22 .7 this implies that 22 .7 is equal to 19 .13 e and 0 .5 .0.
03:27
1 t is 0 so that we can find the value of c and make it more definite.
03:40
So this is 22 .7...