00:01
Oh i've got a little battery i can't stop hang on while i plug in sorry about this just got to get my computer plugged in so it doesn't die mid -solving i can't see what i'm doing shouldn't take too long almost done there that one's going get a spot where i can now maneuver mover okay so our natural ratio of girl births to boy births is 100 to 105 and in china we're told that it's 100 to 114 we conduct a study of boy births and girl births and we get 60 girls and boys in studying randomly chosen 150 recent births and do we believe this percentage so the null hypothesis this gonna i'm not gonna go ahead and explain the whole thing but we're going to be considering a null hypothesis here.
01:09
If this is true, then an alternate hypothesis will be the opposite.
01:26
So it's not the same as the null.
01:28
Ok, so according to this, the claim is this.
01:34
So our claim is that this is 0 .467.
01:43
This is our null.
01:45
And our alternative is not equal to 0 .467.
01:56
That's simple enough.
01:58
So first we need to know the population.
02:01
So we're going to have q equals 1 minus p equals 1 minus 0 .467 equals 0 .533.
02:15
So this is a binomial experimental design.
02:33
And we can check if it follows this.
02:37
150 times 0 .467 which is equal to 150 times 0 .467 is 70 .05 is greater than 5.
02:58
And 150 times 0 .533 which is equal to 79 .95 is greater than 5.
03:17
Both met.
03:20
Normality can be assumed.
03:29
Ok, now we're going to figure out using the level of significance.
03:33
We're going to use our level of significance as 0 .05.
03:38
The test is two -tailed.
03:44
The standard normal distribution.
03:47
Ok, so we already said this is 0 .05.
03:54
And since it's two -tailed, we're going to go this over 2 equals 0 .05 divided by 2 equals 0 .025...