Problem 6 Easy Difficulty

According to one estimate, the first atomic bomb released an energy equivalent to $20 .$ kilotons of TNT. If 1.0 ton of TNT releases about $4.0 \times 10^{9} \mathrm{J}$ , how much uranium was lost through fission in this bomb? (Assume 208 MeV released per fission.)

Answer

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Video Transcript

for this question. First we want to find why see total energy released by the atomic bomb. Total energy. Yakima Days, 20 kilotons of TNT. So, Tony dilettantes and each ton of TNT release about four time state half night juice. Right? So this is in terms of juice, but ah, fission reaction energies in terms, off TV. So you be convenient. If we can convert this into a movie, can do that. My multiplying by one off, 1.6 stand po minus t. Just tell everybody. So this will call vote our energy Jews to MTV. Yeah, We should get five times stent about six. Now we can find a number off Fisher reactions. It's quiet by taking the total number off energy developed by the energy released proficient, which is 208 Emily, right. We should get to a 0.4 times 10 potent for fission reactions. And this will also equal to the number off New Christ that is required. Is also it close to a number off. You're anyone too few five nuclei required. Now we can find What is the mess off you in your or actually homos Uranium. Waas lost. Right? So How much off the west? Immense. Off this amounts all fury. Never. 235 We take 2.4 times 10 poetry for we don't fight debt by the abogados number, which is 6.0 to 2 times 10 fell off a tree. Right, this water thirsty number off, most off your immune to treat five. And then we multiplied it by our moral our mess, which is five grand's Put more. Four uranium 235 This will give us 9.4. Sorry. This would give us 940 Gramps. So this team s off union there. Waas lost.