Question
According to one model that takes into account air resistance, the acceleration $a(t)$ (in $\mathrm{m} / \mathrm{s}^{2}$ ) of a skydiver of mass $m$ in free-fall satisfies$$a(t)=-9.8+\frac{k}{m} v(t)^{2}$$where $v(t)$ is velocity (negative since the object is falling) and $k$ is a constant. Suppose that $m=75 \mathrm{~kg}$ and $k=0.24 \mathrm{~kg} / \mathrm{m}$.(a) What is the skydiver's velocity when $a(t)=-4.9 ?$(b) What is the skydiver's velocity when $a(t)=0 ?$ (This velocity is the terminal velocity, the velocity attained when air resistance balances gravity and the skydiver falls at a constant speed.)
Step 1
We have $a(t)=-4.9$, $m=75 \, \mathrm{kg}$, and $k=0.24 \, \mathrm{kg/m}$. The equation becomes: $$ -4.9=-9.8+\frac{0.24}{75} v(t)^{2} $$ Show more…
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According to one model that takes into account air resistance, the acceleration $a(t)$ (in $\mathrm{m} / \mathrm{s}^{2} )$ of a skydiver of mass $\mathrm{m}$ in free fall satisfies $$ a(t)=-9.8+\frac{k}{m} v(t)^{2} $$ where $v(t)$ is velocity (negative since the object is falling) and $k$ is a constant. Suppose that $m=75 \mathrm{kg}$ and $k=14 \mathrm{kg} / \mathrm{m} .$ $$ \begin{array}{l}{\text { (a) What is the object's velocity when } a(t)=-4.92} \\ {\text { (b) What is the object's velocity when } a(t)=0 ? \text { This velocity is the }} \\ {\text { object's terminal velocity. }}\end{array} $$
DIFFERENTIATION
Higher Derivatives
According to one model that takes into account air resistance, the acceleration $a(t)$ (in $\mathrm{m} / \mathrm{s}^{2} )$ of a skydiver of mass $m$ in free call satisfics $$a(t)=-9.8+\frac{k}{m} v(t)^{2}$$ where $v(t)$ is velocity (negative since the object is falling) and $k$ is a constant. Suppose that $m=75 \mathrm{kg}$ and $k=14 \mathrm{kg} / \mathrm{m} .$ (a) What is the object's velocity when $a(t)=-4.9 ?$ (b) What is the object's velocity when $a(t)=0 ?$ This velocity is the object's terminal velocity.
In skvdiving, the vertical velocity component of the skydiver is typically zero at the moment he or she leaves the plane; the vertical component of the velocity then increases until the skydiver reaches terminal speed (see Chapter 4 ). Let's make a simplified model of this motion. We assume that the horizontal velocity component is zero. The vertical velocity component increases linearly, with acceleration $a_{y}=-g,$ until the skydiver reaches terminal velocity, after which it stays constant. Thus, our simplified model assumes free fall without air resistance followed by falling at constant speed. Sketch the kinetic energy, potential energy, and total energy as a function of time for this model.
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