00:01
This problem involves concepts from solid -state chemistry, so just keep that in mind as you're watching this video.
00:09
Let's note that the letter a represents the side length of a unit cell.
00:14
In order to find the frequency of collision, we first have to understand the planar densities for each of the given planes.
00:21
If we have 100 planes, then our planar density, which i've denoted by the greek letter row, is equivalent to 2 divided by a squared.
00:30
Remember, a is our side length.
00:33
Well, if we have 110 planes, then our density is equivalent to 2 divided by the square root of 2 times 8 squared.
00:42
And finally, if we have 111 planes, our planer density will be equal to 4 divided by the square root of 3 times a squared.
00:54
We are dealing with platinum, and for platinum, the side length of the unit cell is 392 picometers, which is the same.
01:02
Same as 3 .93 times 10 to the negative 8 centimeters.
01:07
So what we're going to do is plug in this value for a into each of the planer density equations for each of the planes we were given.
01:16
So if we have 100 planes, our planer density given that side length of platinum is 1 .29 times 10 to the 15th...