00:03
Hello hi here in this question we have been given a probability data in that probability that a selected worker will be driving a car to work so you'll be using car to work i'm calling that event as c i can say b of c that is using car is given 0 .82 now the second event is given a randomly selected worker will be using public transportation.
00:43
Public transportation.
00:45
That probability i am calling us, probability of p, p for public transportation is given 0 .053.
00:56
Okay, these two data are given.
00:59
Now the question is asking what is the probability that a randomly selected worker will be drives a car or take a public transportation.
01:08
That means we have to find c or p.
01:13
You know, it is given by p of c plus p of p of p minus p of c intersection p.
01:19
But if a person is going by car, he won't be using public transportation.
01:24
So this value particularly becomes zero, since you cannot use both.
01:31
So we just have to add these two.
01:33
When you add these two, we see what value we get.
01:38
So we have to add 0 .82 plus 0 .8 .2.
01:44
0 .053, 0 .873.
01:49
This will be the required answer for the first part of the question.
01:53
Now in the second part, it's asking what is the probability that the selected worker, neither use a car nor public transportation.
02:04
That means we have to find c or p, we already found out.
02:10
We have to find a complement of that event.
02:14
So complement of an event is given by 1 minus probability of that event...