Account for the following observations: (a) In a polar solvent such as water the $\mathrm{S}_{\mathrm{N}} 1$ and $\mathrm{E} 1$ reactions of a $3^{\circ}$ RX have the same rate. (b) $\left(\mathrm{CH}_3\right)_3 \mathrm{Cl}+\mathrm{H}_2 \mathrm{O} \rightarrow\left(\mathrm{CH}_3\right)_3 \mathrm{COH}+\mathrm{HI}$ but $\left(\mathrm{CH}_3\right)_3 \mathrm{Cl}+$ $\mathrm{OH}^{-} \rightarrow\left(\mathrm{CH}_3\right)_2 \mathrm{C}=\mathrm{CH}_2+\mathrm{H}_2 \mathrm{O}+1^{-}$.
(a) The rate-controlling step for both $\mathrm{El}$ and $\mathrm{S}_{\mathrm{N}} 1$ reactions is the same:
$$
\ddot{\mathrm{R}}-\stackrel{\stackrel{-}{-} \mathrm{X}}{\stackrel{\text { slow }}{\longrightarrow}} \mathrm{R}^{+}+\mathrm{X}^{-}
$$
and therefore the rates are the same. (b) In a nucleophilic solvent in the absence of a strong base, a $3^{\circ} \mathrm{RX}$ undergoes an $\mathrm{S}_{\mathrm{N}} 1$ solvolysis. In the presence of a strong base $\left(\mathrm{OH}^{-}\right)$a $3^{\circ} \mathrm{RX}$ undergoes mainly $\mathrm{E} 2$ elimination.