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Hello everyone.
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Let us see the following question.
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We have to account for the following observation.
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Observation a is the boiling point of ammonia is higher than that of phosphine.
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So, ammonia is nh3.
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Phosphine is ph 3.
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When compared to the boiling point, ammonia has a higher boiling point to that of phosphine.
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So we know the simple logic.
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The electro negativity of an atom is inversely proportional.
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To its atomic size.
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So, we know that phosphine being bigger atom, its electronegativity is less.
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So, nitrogen having highest electronegativity will exhibit stronger hydrogen bonding.
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Due to stronger hydrogen bonding, ammonia has higher boiling point.
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So, the reason is stronger hydrogen bonding.
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So let us see option b.
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The melting point of hydrogen selenide, that is h2 s .e, is higher than that of hydrogen sulfide h2 s.
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So the melting point now we are talking about melting point of hydrogen cyanide is greater than the melting point of hydrogen sulfide.
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Now bigger the size depends on the vander wall force.
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So now we have to talk about vanderval force which directly depend on the atomic size as well as atomic mass.
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Now among the amount of the water, you know, along sulfur and selenium, selenium has highest atomic mass, hence it has got highest higher vanderwall force.
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Due to that, its melting point is highest...