Account for the observation that catalytic amounts of $\mathrm{KI}$ enhance the rate of reaction of $\mathrm{RCH}_2 \mathrm{Cl}$ with $\mathrm{OH}^{-}$to give the alcohol $\mathrm{RCH}_2 \mathrm{OH}$.
Since $\mathrm{I}^{-}$is a better nucleophile than $\mathrm{OH}^{-}$, it reacts rapidly with $\mathrm{RCH}_2 \mathrm{Cl}$ to give $\mathrm{RCH}_2 \mathrm{I}$. But since $\mathrm{I}^{-}$is a much better leaving group than $\mathrm{Cl}^{-}, \mathrm{RCH}_2 \mathrm{I}$ reacts faster with $\mathrm{OH}^{-}$than does $\mathrm{RCH}_2 \mathrm{Cl}$. Only a catalytic amount of $\mathrm{I}^{-}$is needed, because the regenerated $\mathrm{I}^{-}$is recycled in the reaction.