00:01
Here's the problem 98 in chapter 19.
00:03
Part a calculate the equilibrium constant for the reaction at 25 degrees.
00:09
So we know that delta g zero of a reaction is equal to negative rt long k.
00:18
So we have long k equal to negative delta g zero divided by rt.
00:27
That's the equilibrium constant we're looking for.
00:30
So delta g0 of a reaction is equal to delta g0 of the product, ch3 c ooh liquid, minus delta g0 of the reactants, which are the ch3oh liquid, and the delta g0 of co gas.
00:55
So this is equal to negative 392 .4 minus negative 166.
01:03
0 .23 minus negative 137 .2.
01:08
That is equal to negative 89 kilojoules.
01:13
Alright, so this is dltz0.
01:18
So long k is equal to negative, negative 89 kilojoules divided by 8 .314 times 10 to minus 3 kilojoules per mole per kelvin, multiply by the temperature, which is 298 kelvin, and this will give you a number of 35 .922.
01:48
So if we solve for k, this will be equal to 4 times 10 to the 15.
01:55
So that's the part for question a.
02:00
Part b, so in the industry, there's reaction runs at temperature above 25...