Acetylacetone (see Exercise $45,$ part a), abbreviated acacH, is a bidentate ligand. It loses a proton and coordinates as acac$^-$ as shown below:
Acetylacetone reacts with an ethanol solution containing a salt of europium to give a compound that is 40.1$\% \mathrm{C}$ and 4.71$\% \mathrm{H}$ by mass. Combustion of 0.286 $\mathrm{g}$ of the compound gives 0.112 $\mathrm{g} \mathrm{Eu}_{2} \mathrm{O}_{3} .$ Assuming the compound contains only $\mathrm{C}, \mathrm{H},$ O, and Eu, determine the formula of the compound formed from the reaction of acetylacetone and the europium salt. (Assume that the compound contains one europium ion.)