00:01
In this problem, we are asked to analyze, given a particular volume in temperature of these two particular gases.
00:11
We have a ceiling and butane gas, and we have their relative hates of combustion.
00:18
A ceiling which is marked a is 49.9 killed jules program.
00:23
And then the butane, which is b, is 49.5 killed rules program and i have their respective formulas on the right hand side.
00:31
So we're basically again asked to analyze if we're given a certain volume in a certain temperature for these gases, which we can pick any, um, scenarios that we like.
00:44
You know, how can we compare? ah, the heats of combustion given a certain volume and again a certain temperature.
00:52
So i went ahead and we'll start a new screen here.
00:55
So, um, i went ahead and picked one leader because that's convenient for calculations.
01:00
And 298 degrees kelvin is pretty much room temperature of 25 degrees celsius.
01:09
So if we would use pv equals in our tea, i can figure out how many moles of gas i have, and from there we can determine how much heat is release.
01:24
So we'll have to convert.
01:26
Aah! these constance here will have to convert those to a formal basis, you know, instead of ah uh, grams.
01:35
But if we go ahead and use it, i'll use one.
01:38
Atmosphere is at sea level.
01:39
Apus atmospheric pressure.
01:41
So we have one times one will have in our gas.
01:47
Constant is 0.8 to 1 and temperatures to 98.
01:54
No.
01:54
What? i divide equal sides by the product of our gas constant temperature.
01:59
I get end equals 0.0 for 09 moles.
02:07
Okay, so we have the same number moles of gas for each of these.
02:12
So if we go over the 1st 1 i went ahead and set it up.
02:16
Already, we have 0.49 moles of a ceiling gas in a 26 grams per mole.
02:24
We're going to go ahead and have 1.6 grams.
02:32
That's where a seedling...