00:01
In this problem, we are practicing how to draw a mechanism and more specifically how we can draw arrow pushing for specific molecules.
00:10
And in this case, we are going to have resonant structure and epoxide ring opening.
00:16
So we're going to go through that process and begin to understand it.
00:19
Now, it's so important that we start learning mechanisms and arrow pushing because this is really the bulk of organic chemistry, understanding how electrons move in a reaction and how we can form products.
00:35
So for part a, we're given this ring structure, specifically this is a benzene ring.
00:40
And we have these two hydrogens coming off of these points here.
00:45
I won't go into the names of these points, but all we need to know is that we have two hydrogens.
00:50
And we are reacting it with deuterium bound to chlorine.
00:54
Now, if you don't know what deuterium is, it's just in isotope.
00:58
Of hydrogen.
00:59
So it has the same properties of hydrogen.
01:01
It's just a little bit heavier because it has a couple more neutrons or one more neutron.
01:07
So what's going to happen here is that in arrow pushing, we always go from electron rich to electron pore.
01:15
That's the direction of our arrow.
01:17
So we're going to have this double bond is going to attack our deuterium.
01:22
And then all of these electrons from this bond are going to move on to chlorine.
01:26
Now the tricky thing here is, is we're going to attack our deuterium.
01:28
And then all of these electrons from this bond are going to we can have resonance in our benzene ring.
01:31
So we need to pick the best structure.
01:33
So these are the structures that can form when we have our carbocation intermediate.
01:38
We have this ring with our two bonds here and a positive charge on the carbon here that's bound to hydrogen and our deuterium...