00:01
The question here wants us to write the electron not structures for the following compounds and basically wants us to find the lone pairs and identify any multiple bonds.
00:12
So let's see for a first.
00:14
So if we write down, we have to, if we want to redraw it, first of all, we have to find available electrons in the whole compound.
00:20
So chlorine gives seven, carbon, of course, four.
00:24
Oxen gives two each, i mean six each.
00:27
Carbon gives up four.
00:29
Hydrogen gives us three so that's going to give us 11 um 23 27 30 total so if we first of all write this end of the structure first as we know that the methyl group here is going to be full of this octet um we have the carbon oxygen and then chlorine here so just looking at it we have 2 4 6 8 10 12 14 already done so we have uh 16 left to go through.
01:00
So first of all, the carbon here wants to form four electrons.
01:07
However, it only has three.
01:09
So oxygen here also wants to have an octet...