Question
Add or subtract as indicated.$$\frac{5}{9-x^{2}}-\frac{4}{x^{2}+4 x+3}$$
Step 1
The first denominator $9-x^{2}$ can be factored as $(3-x)(3+x)$ and the second denominator $x^{2}+4x+3$ can be factored as $(x+1)(x+3)$. So, the expression becomes: $$\frac{5}{(3-x)(3+x)}-\frac{4}{(x+1)(x+3)}$$ Show more…
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