addition-of-an-inert-substance-one-that-does-not-participate-in-the-reaction-does-not-change-the-___

Question

Addition of an inert substance (one that does not participate in the reaction) does not change the _______
of an equilibrium.

Anatole Borisov · Accepted Answer

is this question asked us how an inert substance of fact sequel. So just conserve this generic equilibrium and be reacting to form on addict of these two a plus a B. And so let&#x27;s say we add some compound. See, now what happens is that this is actually going to have no effect on how the equilibrium is. Its let&#x27;s think about why and so do to do that. Remember that the position of an equilibrium is defined by the relationship of Q two K, where K is the equilibrium constant Q. Is the mass acts expression? So that&#x27;s going to be, in this case, the concentration of a B over the concentration of a plus times a conservation of B and so you can pretty obviously see that increasing seat will have zero effect on cue. None of these terms get changed by see there&#x27;s no reliance on those. And so that means the difference between Q and K. There&#x27;s there&#x27;s no is. Nothing is being changed to this actual reaction, so no effects can happen. People position is going to stay this

David Collins · Answer

if we were to have a chemical reaction at Equilibrium Baby in our reactant and BB in our product. If you were toe ADM or reactant ADM or A, this is going to shift the equilibrium to the right in order to slightly offset the addition of the extra amount of A. If, however, we were to add be, then, according to lay shot aliens principle, that&#x27;s going to shift the equilibrium to the left in order to partially offset the increase in B.

Matthew Confer · Answer

at any given temperature. The equilibrium constant doesn&#x27;t change, so okay, constant at a temperature. So as you change the concentrations of reactive and products, the relative concentrations of wrecked in some products will remain the same, but the actual concentrations of them will change, said equilibrium. Position will not change, but the concentrations at equilibrium will.

Evey Z · Answer

we know that for equilibrium, constant K, it is only dependent on the temperature. God, the reaction is running out, and it&#x27;s not dependent on the concentration order Catalyst, President Ward of pressure at which the reaction this running out or how much concentration there is for reactions and product. So if we want to change the equilibrium constant K, the only way to do so is to changed temperature that the reaction is running out.

Steven Swee · Answer

So this problems all about equilibrium and the conditions we have here is that I really have a changing conditions. And the problem says that the Ford reaction is increased or the rate of her four reactions increased more than the rate of the reverse reaction. So in that case that we changed the reaction, conditions were driving the reaction forwards. Okay, so we&#x27;re driving the reaction for over Dr Lee Reaction forward. Then we&#x27;re gonna end up having more products here, right? Because if the four reaction is greater in Bangor, it&#x27;s faster than the reverse reaction. Then equilibrium will be established if, and only if when we have, um, more products than that of the reactant. Then at least go into this changing conditions so you can write your general Que que is equal to see your law mass action formula. But if you joined the reaction forward and we have more products than you have more proxy right and fuel reactions, that means Katie increases if you drive the reaction for them. We also have more products here than the concentration of the products also increases and the concentration of price increases. Then the relative concentration of the reactant CE we&#x27;ll end up decreasing. So this is a result that we have. If we came in reaction conditions and drive the reaction forward, you see the equilibrium constant increasing becomes a concentration of progress is increasing and the concentration of the reactant decreasing.

Jorge Villanueva · Answer

today I&#x27;ll be going over question number 11 Which house you look at reverse ability and university reaction. Would the cheese chemical equilibrium So it turns out No, the reversal. You&#x27;re so go Reactions, Joe to achieve chemical.

Problem

When the volume of a vessel containing a gaseous …

Problem 82 Medium Difficulty

Addition of an inert substance (one that does not participate in the reaction) does not change the _______
of an equilibrium.

Answer

position

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Steven S. Zumdahl, Donald J. DeCoste

Introductory Chemistry

Nadia L.

Morgan S.

Jacquelin H.

Jake R.

Liquids - Intro

Comparison Of Gases Liquids And Solids

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position

Introductory Chemistry

Nadia L.

Morgan S.

Jacquelin H.

Jake R.

Liquids - Intro

Comparison Of Gases Liquids And Solids

Steven S. Zumdahl, Donald J. DeCosteIntroductory Chemistry

Nadia L.

Morgan S.

Jacquelin H.

Jake R.

Steven S. Zumdahl, Donald J. DeCoste

Introductory Chemistry